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Old 2018-12-10, 06:27   #1
a1call
 
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"Rashid Naimi"
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Default Primes of the Form Mod(p,q) = Mod(x,q)

Hi all,
Is there a proof that primes p such that
Mod (p,q) = Mod (x,q)
For any given prime q and integer x such that
0 < x < q
Are Infinity many?
For example for q = 5 and x = 3
Is it provable that the set of primes p:
13, 23, 43, ...
Is infinity large.
Thank you for any reference you may provide.
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Old 2018-12-10, 09:19   #2
Nick
 
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This may help:
https://primes.utm.edu/notes/Dirichlet.html

I think it is also worth experimenting with specific numbers to get a feel for this type of problem (and not just with q prime).
For example:
  1. Prove that there are infinitely many prime numbers.
  2. Prove that there are infinitely many primes which are 3 mod 4.
  3. Prove that there are infinitely many primes that are 1 mod 4.
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Old 2018-12-10, 12:51   #3
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Much obliged Nick,
For the record the Wikipedia entry:
https://en.m.wikipedia.org/wiki/Diri...c_progressions
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Old 2018-12-10, 15:37   #4
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https://primes.utm.edu/top20/page.php?id=14 , too
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Old 2018-12-11, 02:31   #5
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http://mathworld.wolfram.com/Modular...gFunction.html is indirectly related.
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Old 2018-12-11, 02:51   #6
LaurV
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Quote:
Originally Posted by Nick View Post
3. Prove that there are infinitely many primes that are 1 mod 4.
4. Prove that there are infinitely many primes that are 6 mod 7.


Oh... wait... that was the other guy...
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Old 2018-12-11, 03:34   #7
a1call
 
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To much meat on those links.
Thank you Gents both.
Currently I am exhausted from my day job. Digestion will have to wait for another day if at all possible. The straight forward proof seems way too advanced. But Google seems to indicate there has been searches for an "elementary" proof. Will see if that's easier on the mind.

Thank you for all the replies.
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