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#1 |
Nov 2007
home
2510 Posts |
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I think I proved the Goldbach conjecture, here is proof:
This conjecture states that every even number greater than 2 can be expressed as the sum of two primes. This conjecture can be restated as: If X is even and Y is an integer then there exist prime numbers of the form X/2+Y and X/2-Y. A Diophantine equation can be generalized from this: (X/2-Y)(X/2+Y)=M; (X^2)/4-Y^2=M where M is a positive integer, and ((X^2)/4) is a fixed constant. The total number of positive M's is sqrt((X^2)/4). The chance that any of those M's is a semi-prime has a determined lower bound of ~1/4 for moderately sized M and increases as M gets larger. By finding M which is a semiprime the two primes that add to X can be found. Therefore the total number of 2 prime groups that sum to an even integer X has a lower bound of Floor[(sqrt((X^2)/4)/4], which is always greater than one for sufficiently large even integer. Last fiddled with by vector on 2007-11-30 at 11:46 |
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#2 |
"Nancy"
Aug 2002
Alexandria
2,467 Posts |
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> The chance that any of those M's is a semi-prime has a determined lower bound of ~1/4 for moderately sized M and increases as M gets larger.
What exactly do you mean by that? Alex |
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#3 |
"Brian"
Jul 2007
The Netherlands
2×11×149 Posts |
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You seem to be using a probability distribution argument. This would be sufficient to show that "almost all" even numbers are the sum of two primes, but it does not show the complete absence of counter-examples.
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#4 | |
Nov 2007
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52 Posts |
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The proof can be made deterministic by using theorem 3 from http://arxiv.org/PS_cache/math/pdf/0506/0506067v1.pdf Using it the maximum distance between semi primes becomes 26. |
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#5 | |
"Bob Silverman"
Nov 2003
North of Boston
22×1,877 Posts |
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There already exist probabilistic results regarding Goldbach. Look up 'Goldbach exceptions'. For example, it is known that exceptions, *if they exist* have asymptotic density 0. Indeed, the number of possible primes less than P for which exceptions might exist is known to be at most O(P^1/4+epsilon) for any epsion > 0. This does not say whether any exceptions DO exist; merely that there can't be too many if they do. The exponent 1/4 may have been improved since I last looked at this problem. The proofs of this and related results are sieve based and run into the sieve parity problem & the fundamental lemma of the sieve. See Halberstam & Richert's book. |
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#6 |
Nov 2007
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52 Posts |
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nevermind
Last fiddled with by ewmayer on 2007-12-03 at 23:17 Reason: Don't worry - we didn't. |
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