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Old 2018-12-10, 12:48   #1
enzocreti
 
Mar 2018

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Default palindromic prime 111010111

A mathexchange user found that 111010111 divides ((2^3343663-1)*10^1006543+2^3343662-1), the concatenation of two consecutive Mersenne numbers!
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Old 2018-12-10, 12:50   #2
enzocreti
 
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Default other factors

Somebody can find other factors of this number? Besides 691 and naturally 111010111

Last fiddled with by enzocreti on 2018-12-10 at 12:51
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Old 2018-12-10, 13:33   #3
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Originally Posted by enzocreti View Post
Somebody can find other factors of this number? Besides 691 and naturally 111010111
Why?
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Old 2018-12-10, 15:00   #4
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Default factor it

just for fun and because i guess that the next factor is a 666666666...7 prime!
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Old 2018-12-10, 15:27   #5
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Quote:
Originally Posted by enzocreti View Post
just for fun and because i guess that the next factor is a 666666666...7 prime!
Now that's becoming interesting...

What makes you think that the next factor is "a 666666666...7 prime" ?
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Old 2018-12-10, 23:15   #6
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Quote:
Originally Posted by enzocreti View Post
just for fun and because i guess that the next factor is a 666666666...7 prime!
If that is the case, it has more than 80,000 digits.
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