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Old 2019-06-27, 12:31   #1
Mar 2018

17·31 Posts
Default Pg primes congruent to 1111 mod 42^2

pg numbers are so defined:

pg(k)=(2^k-1)*10^d+2^(k-1)-1 where d is the number of decimal digits of 2^(k-1)-1.

pg(8), pg(176006) and pg(541456) are probable primes. They are cogruent to 19 mod (42) and to 1111 mod(42^2).

Do you believe these primes are infinitely many?

primes pg congruent to 19 mod 42 and to 1111 (mod 42^2)?
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