20161015, 05:19  #364 
Romulan Interpreter
Jun 2011
Thailand
2^{3}×19×61 Posts 
yeah, and the graphic looks like it is taking off...

20161015, 14:37  #365 
"Ed Hall"
Dec 2009
Adirondack Mtns
3623_{10} Posts 
And, this c193 doesn't look like anything I could factor easily, either.
I have gotten this far: Code:
100 curves with B1 = 3.0e6 100 curves with B1 = 11.0e6 100 curves with B1 = 43.0e6 2950 curves with B1 = 110.0e6 
20161017, 01:52  #366 
"Ed Hall"
Dec 2009
Adirondack Mtns
3,623 Posts 
I was doing some rewriting of some of my scripts because I noticed the output of the current ecm.py was different from the previous version I was using. Look what I missed (for over a day) until now:
Code:
Sat 2016/10/15 21:19:39 UTC Input number is 1078463040366178656513252069998372090413256075931238262978888504124259070814620248149829075144468079639889184988709479197684315697845414761896628106730638913843128410641236087479218230479393449 (193 digits) Sat 2016/10/15 21:19:39 UTC Run 8 out of 20: Sat 2016/10/15 21:19:39 UTC Using B1=110000000, B2=776278396540, polynomial Dickson(30), sigma=1:395501120 Sat 2016/10/15 21:19:39 UTC Step 1 took 424103ms Sat 2016/10/15 21:19:39 UTC Step 2 took 166986ms Sat 2016/10/15 21:19:39 UTC ********** Factor found in step 2: 32527652508015991688135353490624137200476491466810293 Sat 2016/10/15 21:19:39 UTC Found prime factor of 53 digits: 32527652508015991688135353490624137200476491466810293 Sat 2016/10/15 21:19:39 UTC Prime cofactor 33155268124572048438133784781669020585809197372591704083430677812985365877497549554655661184724402184424723745171751999724006991866553283493 has 140 digits 
20161017, 04:03  #367 
"Frank <^>"
Dec 2004
CDP Janesville
2122_{10} Posts 
Ooh, nice catch!

20161022, 20:40  #368 
May 2009
Russia, Moscow
43×59 Posts 
Next blocker is c191, I've completed ECM up to t45 and 1000@43e6 on it.

20161022, 20:45  #369 
"Ed Hall"
Dec 2009
Adirondack Mtns
3,623 Posts 

20161023, 00:52  #370 
"Ed Hall"
Dec 2009
Adirondack Mtns
3,623 Posts 
With unconnected and mine, are we about at t55?
Are we looking at needing t60? If the above, are we close enough to send for a poly yet? 
20161023, 01:18  #371 
"Curtis"
Feb 2005
Riverside, CA
4,673 Posts 
Yes, I believe you're at roughly a t55. Using the old rule of thumb 0.31*size = t58 = 50% of a t60 = 3 * t55 is enough for GNFS 191, but the Bayesian tool should ask for quite a bit less.
Perhaps another 10001500 at 85e7 and call it good? I can start poly select Tuesday, but I only have a few GPUdays free. A c191 deserves something like a GPUmonth, feasible among the 35 likely forum folks who do poly select. If you do a poly select run, please post your ranges/parameters searched; I reduce stage 1 norm far enough that msieve does NOT search just a slice, so I am likely to overlap work others do. Since a few folks like to search tiny A1, I'll start at 5M to reduce the chance of overlap. 
20161023, 03:03  #372  
"Ed Hall"
Dec 2009
Adirondack Mtns
3,623 Posts 
Quote:
Code:
4200 curves with B1 = 850.0e6 4500 curves with B1 = 2.9e9 Quote:


20161023, 04:48  #373 
"Curtis"
Feb 2005
Riverside, CA
4,673 Posts 
I'll contribute 500 @ 85e7 this week, and I'll wait until you're doing the 3e9 curves before starting poly select. You're not yet halfway through ECM, by either the old rule of thumb or the new tool (interesting the new tool asks for so much ECM!).

20161023, 12:58  #374  
"Ed Hall"
Dec 2009
Adirondack Mtns
E27_{16} Posts 
Quote:
Code:
100 curves with B1 = 3.0e6 100 curves with B1 = 11.0e6 100 curves with B1 = 43.0e6 4500 curves with B1 = 110.0e6 4200 curves with B1 = 850.0e6 4500 curves with B1 = 2.9e9 

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