N congruent to 2^2^n mod(2^2^n+1)

enzocreti · 2020-02-12, 15:03

92020 is congruent to 2^(2^2) mod (2^(2^2)+1) where 2^(2^2)+1 is a Fermat prime

Are there infinitely many numbers N congruent to (2^(2^n)) mod (2^(2n)+1) where (2^(2n)+1) is a Fermat prime?

retina · 2020-02-12, 15:13

Quote:

Originally Posted by enzocreti

92020 is congruent to 2^(2^2) mod (2^(2^2)+1) where 2^(2^2)+1 is a Fermat prime

Are there infinitely many numbers N congruent to (2^(2^n)) mod (2^(2n)+1) where (2^(2n)+1) is a Fermat prime?

Of course there are.

16 mod 17 = 16
33 mod 17 = 16
50 mod 17 = 16
...

So what.

enzocreti · 2020-02-12, 15:14

ok nevermind

2020-02-12, 15:03	#1
enzocreti Mar 2018 1000001111₂ Posts	N congruent to 2^2^n mod(2^2^n+1) 92020 is congruent to 2^(2^2) mod (2^(2^2)+1) where 2^(2^2)+1 is a Fermat prime Are there infinitely many numbers N congruent to (2^(2^n)) mod (2^(2n)+1) where (2^(2n)+1) is a Fermat prime?

2020-02-12, 15:14	#3
enzocreti Mar 2018 17·31 Posts	ok ok nevermind

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