20050102, 17:15  #1 
Nov 2004
UK
2·19 Posts 
Calculating sieving % accuracy
Is there a simple formula for determining what chance a positive integer N, will have of being prime after sieving out prime numbers up to sqrt(N)?

20050102, 19:02  #2  
Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
2^{3}×11^{3} Posts 
Quote:
If by "up to sqrt(N)" you mean "<= sqrt(N)", the probability of N being prime is unity  it is a certainty because if N is composite, it has at least one prime factor <= sqrt(N). If you mean "< sqrt(N)", the only possible way in which it could be composite is if N=p*p, where p is prime. Given that this reasoning is so simple, I wonder if you meant to ask a different question? Paul 

20050102, 19:29  #3 
Jul 2004
Potsdam, Germany
3·277 Posts 
I had the same thought  it could be the case that the sqrt(N) in the question is meant for candidates, not for possible factors.
So the biggest possible factor tested would be sqrt(sqrt(N))... 
20050102, 19:34  #4 
Nov 2004
UK
2×19 Posts 
My error folks  sorry for the darn silly question

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