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#1 |
Apr 2009
2 Posts |
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Hello, Readers.
I have proven that odd-perfect numbers don't exist; it's a 1-page proof that combines Euler's work with that of Jacques Touchard's 1953-paper. Anyone with the knowledge of basic algebra can enjoy it. The answer has been right under our noses!; please visit the root page of my website... www.oddperfectnumbers.com to see for yourself; no additional math is needed to construct this very valid proof. I've also included proofs of both Zarankiewicz's and Richard K. Guy's crossing number formulas on the page Other Short Proofs; just click on the heading to view them. ![]() Best Regards, Bill Bouris |
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#2 |
6809 > 6502
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Aug 2003
101×103 Posts
1089510 Posts |
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This is was posted in the wrong part of the forum.
That makes me think that the proof may have problems too. |
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#3 |
"Forget I exist"
Jul 2009
Dartmouth NS
2·3·23·61 Posts |
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#4 |
Aug 2006
5,987 Posts |
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Paragraph 5 seems to contain the first mistake: "the first factor of the sum is always equal to one-third the size of the number being compared". The previous paragraphs have no mathematical content relating to odd perfect numbers.
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#5 |
"Nancy"
Aug 2002
Alexandria
2,467 Posts |
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I have only skimmed the web page. Would you say this is Misc. Math. material?
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#6 |
"Forget I exist"
Jul 2009
Dartmouth NS
2·3·23·61 Posts |
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#7 | |
"Forget I exist"
Jul 2009
Dartmouth NS
2×3×23×61 Posts |
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okay Q=3 allows it Q=6n+1 or 6n-1 means Q^2 is of the form 6n+1 to make it divisible by three (4x+1)^(4y+1) must be 0 mod 3: 1,5,9 = 1,2,0 mod 3 so the base doesn't always allow 0 mod 3 so next to the exponents so to ensure the biggest factor is 1/3 of the values of the number 1^(4x+1) ,2^(4y+1) , and 0^(4y+1) , must all be 0 mod 3 , and they aren't. even replacing Q=2 doesn't fix that 1^(4y+1) will always be one and hence with Q=2 it will end up as four ( and yes I know that 4 is already not included). of course I'm not familiar to all requirement of the equation you talk of. Last fiddled with by science_man_88 on 2011-05-07 at 22:52 |
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#8 |
Aug 2006
5,987 Posts |
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#9 | |
"Forget I exist"
Jul 2009
Dartmouth NS
2×3×23×61 Posts |
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#10 |
"Nancy"
Aug 2002
Alexandria
1001101000112 Posts |
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Moved to Misc. Math.
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#11 |
Aug 2006
5,987 Posts |
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Science man, I'm not sure what you're trying to show. Since you're talking about an odd perfect number Q must be odd, and hence Q ≠ 2. It's know that Q is divisible by at least eight different primes so in particular Q ≠ 3. 4x+1 is prime, so (4x+1)^(4y+1) is not 0 mod 3.
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