20160914, 09:25  #2619 
"Tapio Rajala"
Feb 2010
Finland
13B_{16} Posts 
Let's see what happens this time. Again below 120 digits with the downdriver.

20160914, 10:58  #2620 
Romulan Interpreter
Jun 2011
Thailand
2^{5}·5·59 Posts 
Well, with the same notation as before, say t=2*F, then its s is 3(1F*)2F, therefore this can never be multiple of 3. To "break", it needs to change the power of 2, and that is only possible if F=Qp is a product of an odd perfect square Q and a prime p with p=1 mod 4. It also works if p or q are void. For that to happen below 100 digits the chances (i.e. bad odds) are:
at ~50 digits: below 1% at ~40 digits: below 1.6% at ~30 digits: about 2.4% at ~20 digits: about 3.6% at ~15 digits: about 4.8% at ~10 digits: about 7.2% We are "safe" for now (yeah, well, I know, "don't jinx it!" hehe). Last fiddled with by LaurV on 20160914 at 11:08 Reason: some wrong calculus 
20160914, 11:08  #2621 
May 2009
Russia, Moscow
13×197 Posts 
< 100 digits again!

20160914, 11:28  #2622 
Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 89<O<88
1C35_{16} Posts 
Booooooooooooooooooo. i8359 = 2 * 7^2 * P91

20160914, 11:34  #2623 
"Forget I exist"
Jul 2009
Dumbassville
10000011000000_{2} Posts 
yeah but luckily since sigma(2^3) = 15 we would need a factor of 3 or 5 to drive it up at last check of what's been said. okay now it's is 2^2 and so would need a 7 I think. and now at 90 digits and a single 2.
Last fiddled with by science_man_88 on 20160914 at 11:49 
20160914, 11:51  #2624  
Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 89<O<88
3·29·83 Posts 
Huzzah!
Code:
Checked 8417 93 (show) 2687306884...12<93> = 2^2 · 3^4 · 8294157051...13<90> Down below 90! 86 and dropping, now 81. We're at the point where the DB is factoring most of the lines by itself. Quote:
Edit: 1205Z and I got a refresh down at 37 digits, subsequent refresh attempts are still pending. Exciting! Termination or more disappointment? Last fiddled with by Dubslow on 20160914 at 12:08 

20160914, 11:53  #2625 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
we are about i8433 right now actually. i8458 is this going to be like yesterday where I couldn't keep up with the edit needed to keep it recent lol. edit: yeah probably ... now at or above i8507. and around 74 digits. might update this edit near my end of edit time. driver:2^4*31 now back at over 90 digits and climbing.
Last fiddled with by science_man_88 on 20160914 at 12:11 
20160914, 12:08  #2626 
"Marc Shelikoff"
Dec 2014
Cambridge, MA
3·5 Posts 
314718 just passed i15,000.
Even though it's a bit (but not extremely) unlikely that the sequence will terminate soon and it's very unlikely that the sequence will catch itself on the way down to create a large cycle, I don't think the probability of those events are in "winning the lottery" territory, and it certainly wouldn't be like the coin flips in Tom Stoppard's "Rosencrantz and Guildenstern Are Dead" at https://youtu.be/KchhSIVwMdY?t=1m30s . 
20160914, 12:09  #2627 
Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 89<O<88
1110000110101_{2} Posts 
Nope, 1208Z and the downdriver went below 20, cycled up to 50 then below 20 again and now back into the 80s with the D4 = 2^4 * 31. Close to 1500 lines added in the last 30 minutes. Edit: 1210Z and we have passed 10,000 total lines! Congrats Ryan, better than nothing
Last fiddled with by Dubslow on 20160914 at 12:10 
20160914, 12:11  #2628 
May 2009
Russia, Moscow
101000000001_{2} Posts 
10000 lines and counting! 2^4*31 isn't easy to survive.

20160914, 12:59  #2629 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
102 digits now i10133 1700 iterations from when I posted in response to dubslow. and 66 minutes roughly. average of roughly 2.33 seconds per iteration roughly. ( to within a minute timing total).
Last fiddled with by science_man_88 on 20160914 at 13:03 
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