20101112, 20:18  #45 
Aug 2006
2·2,969 Posts 

20101112, 20:22  #46  
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Jul 2009
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Quote:
Code:
(11:39) gp > sumdigits(47)+sumdigits(178481) %69 = 4 (16:19) gp > sumdigits(47*178481) %70 = 4 

20101112, 20:24  #47 
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Jul 2009
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okay found a bad exception 2^291 because it uses 3 but if we can reduce it to 2 maybe it still works this is confirmed as a good change lol.
Last fiddled with by science_man_88 on 20101112 at 20:28 
20101112, 20:33  #48 
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Jul 2009
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okay verified exception = 2^371 so how to compensate for exceptions if not to many.0
maybe it works for sumdigits(2^p1) = 4 the hard part is adapting to the case when it's 1. Last fiddled with by science_man_88 on 20101112 at 20:37 
20101112, 20:41  #49 
Jun 2003
7×683 Posts 
See the highlighted part. That is the correct relation. This follows from the fact that sumdigits(x) is equivalent to x%9.

20101112, 20:44  #50 
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Dumbassville
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20101112, 20:46  #51 
Jun 2003
7×683 Posts 

20101112, 20:52  #52 
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20101112, 21:40  #53 
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Jul 2009
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okay i found the exception at 101 point noted. I'll see if either of the idea's work if one does maybe we can limit even more.

20101112, 23:32  #54 
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Jul 2009
Dumbassville
8,369 Posts 
Code:
123456789 246813579 369369369 483726159 516273849 639639639 753186429 876543219 999999999 
20101113, 02:17  #55 
May 2010
Prime hunting commission.
2^{4}×3×5×7 Posts 
I think this is a longwinded circular argument again.. Hopefully it doesn't take 25 pages of posts to realize this.
Last fiddled with by 3.14159 on 20101113 at 02:18 
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