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 2005-12-16, 17:55 #1 Robot2357   Dec 2005 Italy 2 Posts lucas-lehmer theorem Hello, there are various generalization of the lucas-lehmer test,for example one is in http://mathworld.wolfram.com/Lucas-LehmerTest.html for N+1. I think that i've found another generalization to the theorem and proved the sufficent part. but it seems that the necessary part is beyond my mathematical skill.so,suppose that the theorem that i'm speak about it is not know,my question is: do i have to spent months(years?) to gain the right amount of math knowledge and try to complete the proof,and maybe let another person discover the same thing, or it's better to release an incomplete theorem and let the necessary part to someone else?
2005-12-16, 18:04   #2
John Renze

Nov 2005

24×3 Posts

Quote:
 Originally Posted by Robot2357 do i have to spent months(years?) to gain the right amount of math knowledge and try to complete the proof,and maybe let another person discover the same thing, or it's better to release an incomplete theorem and let the necessary part to someone else?
Mathematics is a collaborative endeavor. Post what you know here and people will discuss it.

John

2005-12-16, 19:27   #3
T.Rex

Feb 2004
France

16248 Posts

Quote:
 Originally Posted by Robot2357 Hello, there are various generalization of the lucas-lehmer test, ... I think that i've found another generalization to the theorem and proved the sufficent part.
It is not widely known that the LLT can be used to prove the primality of other numbers than Mersenne numbers. Moreover, many people think that only numbers N for which a factorization of N+1 is known (like Mersenne numbers) can be proved prime by the LLT. As an example, the LLT can also be used for Fermat numbers, see my paper.
It is the same for the Pépin's test. It can be used for proving the primality of a kind of Generalized Fermat Numbers, see Saouter .
Let describe your findings here. Better Mathematicians than me will help you to understand if it is new or not.
Tony

Last fiddled with by T.Rex on 2005-12-16 at 19:32

 2006-12-19, 17:24 #4 hoca     Dec 2006 3 Posts new one S(n)=2*S(n-1)^2 -1 where S(0)=2
2006-12-20, 17:40   #5
ewmayer
2ω=0

Sep 2002
República de California

22×32×17×19 Posts

Quote:
 Originally Posted by hoca S(n)=2*S(n-1)^2 -1 where S(0)=2
A.k.a. "LLT in slight disguise."

2006-12-20, 17:44   #6
R.D. Silverman

Nov 2003

11101001001002 Posts

Quote:
 Originally Posted by hoca S(n)=2*S(n-1)^2 -1 where S(0)=2

 2013-06-15, 03:10 #7 princeps   Nov 2011 22×3 Posts Last fiddled with by princeps on 2013-06-15 at 03:12

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