mersenneforum.org Subproject #2: 500k-600k sequences to 100 digits
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 2009-07-27, 19:31 #23 smh     "Sander" Oct 2002 52.345322,5.52471 29×41 Posts 502304 done Code: Sequence ended: Prime 6 Merges: Merge at n=2837 with 19968, n=643 Merge at n=2867 with 4428, n=5 Merge at n=2883 with 1088, n=1 Merge at n=2884 with 224, n=6 Merge at n=2889 with 80, n=1 Merge at n=2891 with 48, n=2 Taking 502740
 2009-07-27, 23:04 #24 axn     Jun 2003 123616 Posts reserving: 504390, 504532
 2009-07-28, 04:59 #25 Batalov     "Serge" Mar 2008 Phi(4,2^7658614+1)/2 29·313 Posts Done with 501520 501672 501678 501780 501894 501978 all in DB.
 2009-07-28, 08:19 #26 smh     "Sander" Oct 2002 52.345322,5.52471 118910 Posts 502344 Done and in the DB taking 502830
 2009-07-28, 09:14 #27 KriZp     Feb 2007 33×5 Posts unreserving 501426 size 119 i=2586 2^3*3^2*5^2 c99 reserving 502776
 2009-07-28, 14:08 #28 smh     "Sander" Oct 2002 52.345322,5.52471 29×41 Posts 502740 Done and in the DB Taking 503820
 2009-07-28, 23:45 #29 axn     Jun 2003 2·32·7·37 Posts 504532 done. size 103. 2^4*31
 2009-07-29, 00:02 #30 axn     Jun 2003 2×32×7×37 Posts reserving 504168
 2009-07-29, 10:09 #31 10metreh     Nov 2008 2×33×43 Posts Retiring 500010: line 4606, size 100, 2^4*3^2, c90. This might be interesting to extend since it is long and doesn't have a driver. Reserving 502812. Last fiddled with by 10metreh on 2009-07-29 at 10:22
 2009-07-29, 14:14 #32 Greebley     May 2009 Dedham Massachusetts USA 3×281 Posts Done with 500424: size 106, 2^5*3*C104 Size 104 cofactor had ecm run on it without success. If the C104 has two factors as expected, there is a 50% chance that the 2's exponent will increase to 2^6 or more. (Reason: 3+1 = 4 => 2 factors of 2. C104 is 3 mod 4 so if there are two primes, then one is equal to 1 mod 4 and one is 3 mod 4. The one that is one mod 4 adds 1 factor of 2. The one that is 3 mod 4 has a 50% chance of adding 2 factors of 2. With 5 factors of 2 for sigma, the exponent of two will increase. If the 3 mod 4 has more than two factors of 2 (i.e. p+1 divisible by 8), then we have a 2^6 term for sigma and the 2^5 remains.)
 2009-07-29, 20:25 #33 smh     "Sander" Oct 2002 52.345322,5.52471 29×41 Posts 502830 Done Reserving 503280 and 503406 Last fiddled with by smh on 2009-07-29 at 20:37

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