20090727, 19:31  #23 
"Sander"
Oct 2002
52.345322,5.52471
29×41 Posts 
502304 done
Code:
Sequence ended: Prime 6 Merges: Merge at n=2837 with 19968, n=643 Merge at n=2867 with 4428, n=5 Merge at n=2883 with 1088, n=1 Merge at n=2884 with 224, n=6 Merge at n=2889 with 80, n=1 Merge at n=2891 with 48, n=2 
20090727, 23:04  #24 
Jun 2003
1236_{16} Posts 
reserving: 504390, 504532

20090728, 08:19  #26 
"Sander"
Oct 2002
52.345322,5.52471
1189_{10} Posts 
502344 Done and in the DB
taking 502830 
20090728, 09:14  #27 
Feb 2007
3^{3}×5 Posts 
unreserving 501426 size 119 i=2586 2^3*3^2*5^2 c99
reserving 502776 
20090728, 14:08  #28 
"Sander"
Oct 2002
52.345322,5.52471
29×41 Posts 
502740 Done and in the DB
Taking 503820 
20090728, 23:45  #29 
Jun 2003
2·3^{2}·7·37 Posts 
504532 done. size 103. 2^4*31

20090729, 00:02  #30 
Jun 2003
2×3^{2}×7×37 Posts 
reserving 504168

20090729, 10:09  #31 
Nov 2008
2×3^{3}×43 Posts 
Retiring 500010: line 4606, size 100, 2^4*3^2, c90. This might be interesting to extend since it is long and doesn't have a driver.
Reserving 502812. Last fiddled with by 10metreh on 20090729 at 10:22 
20090729, 14:14  #32 
May 2009
Dedham Massachusetts USA
3×281 Posts 
Done with 500424: size 106, 2^5*3*C104
Size 104 cofactor had ecm run on it without success. If the C104 has two factors as expected, there is a 50% chance that the 2's exponent will increase to 2^6 or more. (Reason: 3+1 = 4 => 2 factors of 2. C104 is 3 mod 4 so if there are two primes, then one is equal to 1 mod 4 and one is 3 mod 4. The one that is one mod 4 adds 1 factor of 2. The one that is 3 mod 4 has a 50% chance of adding 2 factors of 2. With 5 factors of 2 for sigma, the exponent of two will increase. If the 3 mod 4 has more than two factors of 2 (i.e. p+1 divisible by 8), then we have a 2^6 term for sigma and the 2^5 remains.) 
20090729, 20:25  #33 
"Sander"
Oct 2002
52.345322,5.52471
29×41 Posts 
502830 Done
Reserving 503280 and 503406 Last fiddled with by smh on 20090729 at 20:37 
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