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2018-01-02, 07:20   #1
George M

Dec 2017

2·52 Posts
Another "how to prove"

Quote:
 Originally Posted by George M $p_{n + 1} \ = \ \{\sum_{k = 1}^{n}(p_{k + 1} \ - \ p_{k}) \ : \ p_m \ = \ m^{th} \ prime \ number\}$
The equation is incorrect, but seemingly correct if you add 2 to the RHS. Can anybody demonstrate a proof?

 2018-01-02, 18:02 #2 danaj   "Dana Jacobsen" Feb 2011 Bangkok, TH 32·101 Posts Moved from a a post on a Prime Gap Searches thread.
2018-01-02, 18:08   #3
science_man_88

"Forget I exist"
Jul 2009
Dumbassville

26·131 Posts

Quote:
 Originally Posted by George M The equation is incorrect, but seemingly correct if you add 2 to the RHS. Can anybody demonstrate a proof?
You are summing the prime gaps, you need to add 2 because 2 is tje first prime.

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