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 2017-01-09, 19:05 #1 science_man_88     "Forget I exist" Jul 2009 Dartmouth NS 845010 Posts what should I post ? most of what I can think of I probably already have posted somewhere like the trivial results that $2^m{M_n}^2 \equiv M_{n-1}+2^m \pmod {M_{n+m}}$ edit: yep so trivial I messed up it's statement. basically I was just using the fact that: 1(2x+1)^2 = 4x^2+4x+1 = x(4x+3)+(x+1) 2(2x+1)^2 = 8x^2+8x+2 = x(8x+7)+(x+2) which technically is: $2^m{M_n}^2 \equiv M_{n-1}+2^m \pmod {M_{n+m+1}}$ because m=0 for the 1 case. so this is just a specific case of a more general algebraic fact. Last fiddled with by science_man_88 on 2018-01-20 at 23:56 Reason: Fixed basic algebra mistakes
 2017-01-13, 01:23 #2 science_man_88     "Forget I exist" Jul 2009 Dartmouth NS 204028 Posts closest thing I could think of to post is how some of the things on these forums are connected like: mersenne prime exponents linking to cunningham chains of the first kind (as well as other primes if you don't accept length 1 chains if you accept that the following hold) a mersenne prime exponent>3 can only be the last member of a cunningham chain of the first kind or the first term in a chain that starts with a prime p=4n+1, or a 1 chain length prime of form 4n+3. the Lucas Lehmer test in reduced form is similar to TF okay not sure of what else to put here can't think of any more right now even though I could say maybe some computer science things. Last fiddled with by science_man_88 on 2017-01-13 at 02:40 Reason: typo
 2017-04-03, 23:42 #3 science_man_88     "Forget I exist" Jul 2009 Dartmouth NS 2×52×132 Posts mostly playing with the reduced LL test today Code: 2(k)(n)+1 -> 2(2(k)(n)+1)^2-1 -> 8(k^2)(n^2)+8(k)(n)+1 -> 8(k)(n)(n+1)+8(k^2)+8(k)+1 a(2(k)(n)+1)->2(a(2(k)(n)+1))^2-1 -> (a^2)(2(2(k)(n)+1)^2-1 ->(a^2)(8(k^2)(n^2)+8(k)(n)+1) -> (a^2)(8(k)(n)(n+1)+8(k^2)+8(k)+1) k are related to fermat quotients a are the values that are s_n divided by the mersenne primes in that form of the test.
 2017-04-07, 11:59 #4 MisterBitcoin     "Nuri, the dragon :P" Jul 2016 Good old Germany 23×3×37 Posts The connection between primes and the riemann zeta-function is very exiting. Maybe somethink for you. ;) Check it out: https://en.wikipedia.org/wiki/Riemann_zeta_function And one more link: https://en.wikipedia.org/wiki/Proof_..._zeta_function Last fiddled with by MisterBitcoin on 2017-04-07 at 12:01
2017-04-07, 12:20   #5
science_man_88

"Forget I exist"
Jul 2009
Dartmouth NS

2·52·132 Posts

Quote:
 Originally Posted by MisterBitcoin The connection between primes and the riemann zeta-function is very exiting. Maybe somethink for you. ;) Check it out: https://en.wikipedia.org/wiki/Riemann_zeta_function And one more link: https://en.wikipedia.org/wiki/Proof_..._zeta_function
I'm not quite that advanced at last check. I would need to read up on complex exponentiation again I think.

 2017-04-14, 20:57 #6 science_man_88     "Forget I exist" Jul 2009 Dartmouth NS 2·52·132 Posts closest to that I have are numberphile videos mostly right now: it relates to too much for me to deal with and L-function stuff exist in PARI/gp but I'm not good enough at knowing what to put in to get anything back useful to me.
 2017-12-16, 21:44 #7 science_man_88     "Forget I exist" Jul 2009 Dartmouth NS 2·52·132 Posts twitter update At least on my account, there's now an option to post 25 tweets in a tweet thread. Each one can contain a poll of up to 4 options. What are some potentially useful topics to poll about, other than worst intersection in a municipality ?
 2017-12-16, 22:57 #8 Nick     Dec 2012 The Netherlands 2×7×131 Posts I assume they make their money by selling information about users. So the question is what you want that information about you to say, perhaps?
2017-12-16, 23:26   #9
science_man_88

"Forget I exist"
Jul 2009
Dartmouth NS

210216 Posts

Quote:
 Originally Posted by Nick I assume they make their money by selling information about users. So the question is what you want that information about you to say, perhaps?
I was thinking at one point of making a poll of all 101 products my job placement place makes and seeing what people like. of course I have so few followers, that it probably wouldn't hit any of the bakery's customers.

Last fiddled with by science_man_88 on 2017-12-16 at 23:27

 2018-01-20, 23:10 #10 science_man_88     "Forget I exist" Jul 2009 Dartmouth NS 2×52×132 Posts What's the significance of the fact... That the residues mod some mersenne in the LL test, are quadratic residues mod the next mersenne. Reason I think this to be true: Sqr(A*p+b)= A^2(p^2)+ b^2(1^2)-b mod 2p+1 and two parts of that simplify to quadratic residues. Failure would only happen if the sums/ differences of quadratic residues wasn't a quadratic residue ( guess I may be wrong). Last fiddled with by science_man_88 on 2018-01-21 at 00:16
 2018-01-27, 19:27 #11 science_man_88     "Forget I exist" Jul 2009 Dartmouth NS 2×52×132 Posts Better than emirp ?

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