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#1 |
Dec 2008
Boycotting the Soapbox
24·32·5 Posts |
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What advanced knowledge do we have about the factors of the following numbers?
P = (k*2^m)^(2^n)+1 where k is an odd 32-bit number, and m ~ n. The idea is to use Proth's theorem for a primality check and do convolutions using Schoenhage-Strassen with carries in base-(k*2^m). |
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#2 |
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
990910 Posts |
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Factors will be = s*2n+1+1.
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