20181023, 04:54  #12  
May 2004
2^{2}·7·11 Posts 
Quote:
(to be continued). 

20181024, 04:47  #13  
May 2004
2^{2}·7·11 Posts 
A tentative definition
Quote:
Let N be a squarefree composite number such that atleast two of its prime factors are inverses (mod P^k) where k is a natural number. Then N is a tortion free number of degree k. (P is a prime number less than the largest prime factor of N). Last fiddled with by devarajkandadai on 20181024 at 04:51 Reason: To make it clearer 

20181024, 05:51  #14  
May 2004
308_{10} Posts 
A tentative definition
Quote:


20181024, 11:04  #15  
May 2004
2^{2}·7·11 Posts 
Quote:


20181024, 12:26  #16 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 

20181024, 13:45  #17 
"Forget I exist"
Jul 2009
Dumbassville
20C0_{16} Posts 

20181024, 20:34  #18  
Aug 2006
2×29×101 Posts 
Quote:


20181028, 05:39  #19 
May 2004
134_{16} Posts 
A tentative definition
Time to define inverses of higher order: let x and y be such that xy+1 = a*p^k+1 where a is a constant belonging to N, k is a natural number and p is a prime number. Then x and y are inverses of degree k.

20181029, 12:33  #20 
May 2004
134_{16} Posts 
A tentative definition

20181029, 14:41  #21 
"Serge"
Mar 2008
Phi(3,3^1118781+1)/3
11×19×43 Posts 
Hint: P=2, and P^k+1 is a semiprime.

20181029, 15:13  #22 
Feb 2017
Nowhere
3·5^{2}·41 Posts 

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