A Sierpinski/Riesel-like problem

[sweety439]

1,7
2,84
3,20
4,2285
5,5
6,1
7,6
8,1
9,1
10,1
11,0
12,3
13,1
14,1
15,2
16,3
17,3
18,2
19,4
20,1
21,9
22,2
23,4
24,1
25,3
26,2
27,2
28,10
29,37
30,1
31,2
32,2
33,1
34,1
35,4
36,1
37,0
38,2
39,0
40,2
41,955
42,775
43,4
44,3
45,1863
46,249
47,6
48,1
49,13
50,2
51,22
52,3
53,17
54,7
55,2
56,1
57,0
58,4
59,12
60,14
61,1
62,24
63,36
64,0
65,1
66,2
67,2
68,1
69,1
70,1
71,2
72,24
73,1
74,3
75,1000
76,1
77,7
78,1
79,4
80,3

With CK=81

k=4 prime found by the project for k<=12 and bases <= 1024

k = 11, 37, 39, 57, 64 remain at n=2000

[sweety439]

1,3
2,2
3,1

With CK=4

Conjecture proven

[sweety439]

1,5
2,2
3,3
4,1
5,2
6,86
7,1
8,1
9,9
10,2
11,1
12,1
13,8
14,1
15,1
16,17
17,1
18,1
19,1
20,1
21,6
22,4
23,2
24,6
25,1
26,1
27,7
28,4
29,2
30,6
31,1
32,1
33,1
34,2
35,1
36,1
37,2
38,1
39,1
40,1
41,13
42,12
43,1
44,71
45,184
46,1
47,1
48,1
49,171
50,41
51,5
52,7
53,1174
54,2
55,2
56,1
57,1
58,8
59,3
60,67
61,4
62,2
63,1
64,1
65,0
66,1
67,1
68,2
69,2
70,1
71,1
72,2
73,1
74,6
75,7
76,1
77,2
78,29

With CK=79

k = 65 remain at n=2000

[VBCurtis]

If you can't figure out how to stop spamming the forum with multiple one-line posts ten minutes apart, we will figure it out for you.

The less attention you draw to yourself with this inane crap, the more likely you are to not be banned. Why is this so hard for you to grasp?

[sweety439]

searched to n=2000, see the text file for the status, 0 if no (probable) prime found for this k

CK=4174

[Stargate38]

@VBCurtis: You shouldn't be banning people for posting stuff in their blog. As long as the posts are in the blog area, you shouldn't count them towards bans. Seriously, that's what blogs are for. They're for posting whatever you want, as long as it doesn't have anything illegal/obscene in it. Also, please unban ONeil (I have no idea why he/she/they would still be banned, given what's in the last post) and Samuel immediately, and give the latter a blog of their own to post in.

TL;DR: You should let people post whatever they want in their blog, as long as it's not illegal.

There's also the possibility that Sweety439 might be special needs, and therefore might not be able to understand certain things.

[sweety439]

1,3
2,8
3,6
4,1865

With CK=5

Conjecture proven

[sweety439]

1,3
168,2
335,1
502,3
669,1
836,3
1003,1
1170,14
1337,2
1504,3
1671,2
1838,4
2005,1
2172,0
2339,12
2506,1
2673,1
2840,1
3007,27
3174,3
3341,1
3508,1
3675,1
3842,2
4009,4
4176,1
4343,1781
4510,10
4677,28

With CK=4744

(Condition 1):

All k where k = m^2 and m = = 5 or 8 mod 13:
for even n let k = m^2 and let n = 2*q; factors to:
(m*168^q - 1) * (m*168^q + 1)
odd n:
factor of 13

This includes k = 25, 64, 324, 441, 961, 1156, 1936, 2209, 3249, 3600

(Condition 2):

All k where k = 42*m^2 and m = = 3 or 10 mod 13:
even n:
factor of 13
for odd n let k = 42*m^2 and let n=2*q-1; factors to:
[m*2^(2q-1)*42^q - 1] * [m*2^(2q-1)*42^q + 1]

This includes k = 378, 4200

Only list k == 1 mod 167 since other k are already in CRUS

the only remain k with k == 1 mod 167 is 2172

other remain k are {53, 495, 584, 586, 948, 1364, 1416, 1429, 1512, 1626, 1741, 1743, 1754, 1938, 2237, 2263, 2599, 2627, 2848, 2852, 3067, 3106, 3119, 3238, 3314, 3407, 3574, 3678, 3769, 3795, 3797, 3844, 4016, 4328, 4382, 4549, 4614, 4642, 4668, 4707, 4723}, see CRUS

[sweety439]

1,(full algebra factors)
2,1
3,2
4,(full algebra factors)
5,1
6,1
7,1
8,1
9,(full algebra factors)
10,1
11,1
12,1
13,2
14,2
15,1

With CK=16

All k = m^2 for all n; factors to:
(m*13^n - 1) * (m*13^n + 1)

This includes k = 1, 4, 9

Conjecture proven

[sweety439]

1,17
2,166428
3,1
4,3
5,38
6,1
7,3
8,15422
9,7
10,1
11,108
12,1
13,13
14,2
15,1
16,1
17,2
18,360
19,1

With CK=20

k = 2, 8 primes given by CRUS

Conjecture proven

[sweety439]

1,181
2,2
3,60
4,1
5,0
6,2
7,68
8,1
9,1
10,1
11,138
12,2
13,5
14,1
15,0
16,1
17,1
18,1
19,2
20,4
21,1
22,1
23,32
24,2
25,1
26,3
27,20
28,1
29,3
30,31
31,2
32,1
33,3
34,1
35,6
36,1
37,1
38,2
39,4
40,6
41,1
42,72
43,2
44,1
45,1
46,3
47,2
48,5
49,5
50,2
51,0
52,1
53,11
54,2
55,2
56,2
57,5
58,13
59,4
60,1
61,45
62,1
63,2
64,7
65,1
66,14
67,4
68,83
69,1
70,1
71,20
72,6
73,51
74,1
75,0
76,2
77,5
78,1
79,2
80,1
81,3
82,3
83,4
84,2

With CK=85

k = 5, 15, 51, 75 remain at n=2000