20110804, 00:27  #24 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 
all the code does is calculate the sum of the divisors of the number x then minus x from the total y amount of time concatenating the last result into a vector. then displays the vectors in PARI.

20110804, 00:31  #25  
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
Quote:
Code:
trying(x)=a=[x];until(isprime(x)sigma(x)x==x,if(isprime(x),break(),x=sigma(x)x;a=concat(a,x)));a 

20110817, 06:24  #26  
May 2011
France
7·23 Posts 
i' m back!!!!
I don't know PARI
Quote:
Who are x and Y Who are a and b What means a=[x]? Why sigma(x)x==x, a=concat(a,x) => a=a*x ????? I understood that B begin at one and is inc is one. It's true? You don't have prime factor ans the power: you compute directly x? Thanhs John 

20110817, 18:22  #27 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
They are given values the function uses as inputs
They are variables used to calculate the result of the function. it turns a into a vector with x as a element of the vector. Because, sigma(x) = sum of all divisors including x which would not be added in an aliquot sequence as it is not proper. to get rid of the x we simply subtract it to form the new correct x value. it means http://en.wikipedia.org/wiki/Concatenation Last fiddled with by science_man_88 on 20110817 at 18:23 
20110817, 19:07  #28 
May 2011
France
A1_{16} Posts 
Pari
Pour moi concat c'est pour des characteres pas des numerics et concatenet des numriques cela ne veut rien dire
Mes outils sont presque prets A moi les ALIQOT John 
20110820, 07:17  #29 
May 2011
France
7×23 Posts 
PATI
Code:
trying(x)=a=[x];until(isprime(x)sigma(x)x==x, if(isprime(x),break(), x=sigma(x)x; a=concat(a,x))); a X is the value to factorize [x] is a vector with primes numbers for each value of the vector you verify: isprime(x)sigma(x)x==x if(isprime(x),break(), stop because X is prime You compute a New X x=sigma(x)x; you cumul the result in a a=concat(a,x) and you do a mysterery: a; ?????? My questions are How do youu fill the vector? where do you div x? where are the power of P(if exist) What is wrong.... John 
20110820, 14:32  #30  
"Forget I exist"
Jul 2009
Dumbassville
20C0_{16} Posts 
Quote:


20110821, 15:49  #31 
May 2011
France
7·23 Posts 
X
Sorrry the Pascal is NOT CASE SENSITIVe
Prime=PRimE=PRIME=PrImE.... so for me X=x John Last fiddled with by JohnFullspeed on 20110821 at 15:51 
20110821, 16:20  #32 
Aug 2006
3·5^{2}·79 Posts 

20110821, 16:24  #33 
Aug 2006
3·5^{2}·79 Posts 
The step
a=concat(a,x) adds x to the end of the vector a. I don't know what you mean. I don't know what you mean by this either. 
Thread Tools  
Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Broken aliquot sequences  fivemack  FactorDB  45  20200516 15:22 
Broken aliquot sequences  schickel  FactorDB  18  20130612 16:09 
A new theorem about aliquot sequences  garambois  Aliquot Sequences  34  20120610 21:53 
Beginning driver/downdriver questions  biwema  Aliquot Sequences  6  20110822 20:41 
New article on aliquot sequences  schickel  mersennewiki  0  20081230 07:07 