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Old 2007-05-30, 23:33   #1
meknowsnothing
 
May 2007

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Default Congruence notation

I read about the AKS primality test. That algorithm uses the relation (x - a)^n = (x^n - a) mod (n, x^r - 1). What does it mean? I know that a=b mod c <=> c|a-b but the notation a=b mod (c,d) is new for me. Or is (n,x^r-1) just the greatest common divisor of n and x^r-1?
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Old 2007-05-31, 03:32   #2
wblipp
 
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"William"
May 2003
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Quote:
Originally Posted by meknowsnothing View Post
I read about the AKS primality test. That algorithm uses the relation (x - a)^n = (x^n - a) mod (n, x^r - 1). What does it mean?
Must be something going around. fetofs asked the same question earlier this month. The answers are pretty good.

http://www.mersenneforum.org/showthread.php?t=8119
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