Mersenne Prime Exponent Distribution - Page 2

Dubslow · 2016-03-16, 04:29

I've been known to give RDS perhaps more leeway than he deserved, but can we please

this troll already

axn · 2016-03-16, 04:40

Quote:

Originally Posted by Dubslow

can we please

this troll already

As long as their activities are confined to specific sub-fora and/or specific threads, I am happy to leave them be. We're not obliged to spend time on them in anyway. Ignore list is probably the best option in context.

paulunderwood · 2016-03-16, 04:44

Quote:

Originally Posted by PawnProver44

Except for 1, there is always a prime p such that 2^p-1 is prime between 10^n and 1.5*10^n.

There is no known proof that there are an infinity of Mersenne primes.

Also the gap between M37 and M38 exponents is greater than "1.5"

Sorry for not complying with...

PawnProver44 · 2016-03-16, 04:48

The Few exponents I am referring to are 13, 107, 127, 1279, 11213, 110503, 132049, 1257787, 1398269, 13466917.......

The pattern probably continues for 9 digits as well, so there is probably a mersenne prime between 2^99999999 and 2^149999999

Dubslow · 2016-03-16, 04:55

Quote:

Originally Posted by axn

As long as their activities are confined to specific sub-fora and/or specific threads, I am happy to leave them be. We're not obliged to spend time on them in anyway. Ignore list is probably the best option in context.

Congratulations PawnProver44, you are the first ever member of my ignore list.

PawnProver44 · 2016-03-16, 05:44

Quote:

Originally Posted by Dubslow

Congratulations PawnProver44, you are the first ever member of my ignore list.

I am not a troll! please.

ET_ · 2016-03-16, 15:16

Code:

Trial-factoring M71324207525210468041 in [2^1, 2^105-1]
M71324207525210468041 has 0 factors in [2^1, 2^105-1].

Anybody cares to go further?

PawnProver44 · 2016-03-16, 18:58

Trial factoring may not be the best idea here.

science_man_88 · 2016-03-16, 19:07

Quote:

Originally Posted by PawnProver44

Trial factoring may not be the best idea here.

well we know LL will likely take longer etc. at some point at which case a primality ( typically done with the LL test for Mersennes) or factoring algorithm of some sort may be the way to find it composite.

PawnProver44 · 2016-03-16, 19:11

right... There is also the N+1 primality test to apply.

Batalov · 2016-03-17, 02:16

Quote:

Originally Posted by PawnProver44

right... There is also the N+1 primality test to apply.

Talk is cheap. Do it. Or STFU, at last.

2016-03-16, 15:16	#18
ET_ Banned "Luigi" Aug 2002 Team Italia 11371₈ Posts	Code: Trial-factoring M71324207525210468041 in [2^1, 2^105-1] M71324207525210468041 has 0 factors in [2^1, 2^105-1]. Anybody cares to go further?

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2016-03-16, 04:29	#12
Dubslow Basketry That Evening! "Bunslow the Bold" Jun 2011 40<A<43 -89<O<-88 3·29·83 Posts	I've been known to give RDS perhaps more leeway than he deserved, but can we please this troll already

2016-03-16, 04:48	#15
PawnProver44 "NOT A TROLL" Mar 2016 California 197 Posts	The Few exponents I am referring to are 13, 107, 127, 1279, 11213, 110503, 132049, 1257787, 1398269, 13466917....... The pattern probably continues for 9 digits as well, so there is probably a mersenne prime between 2^99999999 and 2^149999999

2016-03-16, 18:58	#19
PawnProver44 "NOT A TROLL" Mar 2016 California 197 Posts	Trial factoring may not be the best idea here.

2016-03-16, 19:11	#21
PawnProver44 "NOT A TROLL" Mar 2016 California 197 Posts	right... There is also the N+1 primality test to apply.