mersenneforum.org November 2016
 User Name Remember Me? Password
 Register FAQ Search Today's Posts Mark Forums Read

 2016-11-01, 13:35 #1 Xyzzy     "Mike" Aug 2002 3·2,689 Posts November 2016
 2016-12-06, 16:41 #2 R. Gerbicz     "Robert Gerbicz" Oct 2005 Hungary 22×5×73 Posts The official solution is at: https://www.research.ibm.com/haifa/p...ember2016.html That is Motty Porat's math solution (this earned a star for him, the only star solution!). My sent solution was: "The minimal is N=42, and one possible solution: 0 13 29 11 12 19 10 11 21 9 10 23 8 9 25 7 8 27 6 7 29 5 18 19 4 17 21 3 16 23 2 15 25 1 14 27 found this in 18 minutes with a backtracking code: for each month we store the possible triplets: if we fix the i-th month's triplet, then we store those triplets in the further months (j=i+1,..,12) for that we don't get a violation for the (i,j) month dual. In this way we ensure that (k,j) month dual will be valid for all ki). If we reach i=12, then obviously we found a solution." [...] ps. After I have sent this observed that we can use symmetry: we can assume that N1

 Thread Tools

 Similar Threads Thread Thread Starter Forum Replies Last Post Batalov Puzzles 3 2017-12-08 14:55 R. Gerbicz Puzzles 3 2015-12-01 17:48 MattcAnderson Puzzles 2 2015-11-07 17:54 Xyzzy Puzzles 1 2014-12-02 17:40 Oddball Twin Prime Search 19 2011-11-18 17:56

All times are UTC. The time now is 11:54.

Fri Apr 23 11:54:51 UTC 2021 up 15 days, 6:35, 0 users, load averages: 2.14, 1.76, 1.64

Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2021, Jelsoft Enterprises Ltd.

This forum has received and complied with 0 (zero) government requests for information.

Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation License, Version 1.2 or any later version published by the Free Software Foundation.
A copy of the license is included in the FAQ.