20101126, 23:21  #1 
2^{2}·11·211 Posts 
Reserve Exponent to Completion
Is there a way to reserve an exponent to completion? Meaning, if it has never been assigned to anyone, do the TF, P1, ECM and LL just by putting in the exponent number?

20101127, 04:06  #2 
Jun 2003
7×167 Posts 
An exponent is "complete" for the purposes of prime search either when a factor is found or when it has two matching LL residues. ECM is not normally part of this process as it is not costeffective in CPU terms. Instead, we do ECM on small exponents which are already "complete" in an effort to find more factors.
If you take a DC assignment, it will by definition be "complete" when you have finished. If you take an LL assigment, you will automatically do any remaining TF and P1 necessary on it, prior to starting the LL. It's not probably not a good idea for both the firsttime LL and the DC to be done by the same user, and certainly not on the same machine. If you take a TF or P1 assignment and want to do the LL on it too, you could try changing the assigment in your worktodo file to "Test=...". This might work, though I've never tried it. Bear in mind that you cant just change the "Test=" part. The parameters need to be changed as well. 
20101127, 04:54  #3 
3·3,187 Posts 
thanks for the reply. Yea I was just thinking, for an exponent, if there's been no trial factoring on it started yet, I would want to start trial factoring before doing P1 and eventually LL on it. Do I have to do all the steps manually? i.e. get manual assignment for trial factoring up to 63, then up to 64, then up to 65 etc and if none of these have a factor, then get a manual assignment for P1 and if that doesn't have any factors, then get a manual assignment for LL or can I just say get a manual assignment for LL and it'll automatically go through the paces of trying the trial factoring first and then doing the P1 and then will start LL? But from what you said here, it looks like if there has never been any TF and P1 that it will automatically star the trial factoring on it and not jump straight to LL? " If you take an LL assigment, you will automatically do any remaining TF and P1 necessary on it, prior to starting the LL."

20101127, 05:00  #4  
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
10100100100011_{2} Posts 
Quote:
So, if you have a crazy formula that tells you what the next prime will be, you can ask for the exponent. If it is not already assigned, you should get it. 

20101127, 05:19  #5 
3·139 Posts 
Thanks Uncwilly. I had another post that hasn't shown up yet, since I'm unregistered, but you answered my question. Mr. P1 did as well, but I Just wasn't too sure until I read your reply.
Thanks 
20101127, 11:45  #6  
Jun 2003
2221_{8} Posts 
Quote:
There's nothing to stop our guest from finding an unassigned exponent that has only been TF'ed to 64 bits, taking it as an LL assignment, and reducing the "TFed to" parameter, so that the client redoes the lover level TFs. This won't actually make a great deal of difference to the overall running time. I'm not sure, however, that the client is even capable of TF at very low bit levels. I think there may be some, "this is definitely not necessary" code in there. Last fiddled with by Mr. P1 on 20101127 at 11:47 

20101127, 14:27  #7  
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
7×13×47 Posts 
Quote:
q=2*1*100043+1=200087 And Prime95 finds it. With: Factor=100043,0,40 It works: [Work thread Nov 27 08:24] Starting trial factoring of M100043 to 2^40 [Work thread Nov 27 08:24] M100043 has a factor: 200087 

20101128, 11:00  #8  
Banned
"Luigi"
Aug 2002
Team Italia
2^{2}·7·173 Posts 
Quote:
Luigi 

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