20170513, 11:22  #1 
Mar 2016
2^{4}·3^{3} Posts 
the multiplicativ structur of the discriminant for quadratic polynomials
A peaceful day for all,
there is a nice table for the discriminant of special quadratic polynomials and their resulting pattern: http://devalco.de/periodic_system_of...riminants.html It is a preview and i think their should be some more information added. Nevertheless for those mathematicans having fun with primes i try to build up a periodical system which seems to have some relationship with the periodical system of chemical elements. I have calculated the polynomial f(n)=n²+bn+c in some limits for b and c, chosen only the polynomials which construct some infinite series of prime numbers, and tried to get a relationship for those discriminants which consists of two primes and the discriminants with one prime. Mathematical feedback and suggestion for improvements are welcome Greetings from the primes Bernhard 
20170513, 11:48  #2  
"Forget I exist"
Jul 2009
Dartmouth NS
10000100000010_{2} Posts 
Quote:
Last fiddled with by science_man_88 on 20170513 at 12:17 

20170524, 15:43  #3 
Mar 2016
2^{4}·3^{3} Posts 
A peaceful evening for all,
there is a collection of monic quadratic irreducible polynomials f(n)=n^2+bn+c where the discriminant is b^24c. I choose the polynomials with discriminant=p1*p2, where p1 and p2 are primes and add the polynomials with discriminant p1 and p2 : http://devalco.de/triple_system.php It seems to be that the three polynomials with discr. = p1*p2, p1 and p2 "contains" all primes. If someone has a good mathematical proof, it would be nice to get a description. Have a lot of fun with primes Bernhard 
20170527, 01:33  #4 
"Matthew Anderson"
Dec 2010
Oregon, USA
2^{3}×149 Posts 
Hi Bernhard and everybody,
I appreciate the work you did on your webpage Bernhard. I was able to scroll down and choose a polynomial and then see the sequence when the input is an integer. Keep up the good work. Regards, Matt 
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