13x666=2020

petrw1 · 2020-11-25, 16:00

In honor of UncWilly's New Math:
https://www.mersenneforum.org/showpo...postcount=1068

Find a formula using only 13 and 666 to get 2020.
You can only use +. -, x, /, ^, !, √

1. Find an answer with the fewest numbers (not digits).
2. Find an answer with the same number of each; and the fewest.

For example my first attempt uses 11 numbers.
So its an answer for 1. but not for 2.
666+666+666+13+13-(13+13)/13-(666+666)/666.

Viliam Furik · 2020-11-25, 16:30

13*13*13-13*13-(13+13+13+13+13+13+13+13)/13 = 2020

Viliam Furik · 2020-11-25, 16:33

Quote:

Originally Posted by Viliam Furik

13*13*13-13*13-(13+13+13+13+13+13+13+13)/13 = 2020

13*(13*13-13)-(13+13+13+13+13+13+13+13)/13 = 2020

13 13's

petrw1 · 2020-11-25, 17:02

Quote:

Originally Posted by Viliam Furik

13*(13*13-13)-(13+13+13+13+13+13+13+13)/13 = 2020

13 13's

So next I'll expect 666 666s?

VBCurtis · 2020-11-25, 17:11

In the spirit of the original formula, solutions should use both 13 and 666.

Gelly · 2020-11-25, 17:19

Trivial improvement to the original solution - 10 numbers

666+666+666-(666+666+666+666)/666+13+13

henryzz · 2020-11-25, 17:39

Not much of a record but the first to use ^
(13+13+13+13)/13 + (13+13/13)*(13-13/13)^((13+13)/13)

7 of each
(666+666+666+666)/666 + (13+666/666)*(13-13/13)^((13+13)/13)

matzetoni · 2020-11-25, 18:51

Trial and error got me down to 9 numbers:

2020 = 666+((13+13)/13)*(666+13-(13+13)/13)

Ensigm · 2020-11-25, 19:37

Quote:

Originally Posted by henryzz

Not much of a record but the first to use ^
(13+13+13+13)/13 + (13+13/13)*(13-13/13)^((13+13)/13)

7 of each
(666+666+666+666)/666 + (13+666/666)*(13-13/13)^((13+13)/13)

The second one is really a smooth answer!

Ensigm · 2020-11-25, 19:48

((666+666)/666)**(13-(13+13)/13)-13-13-(666+666)/666

6 each.

Ensigm · 2020-11-25, 19:52

** means ^——I was using python as my calculator, as many would have guessed it.

Written with ^, my answer would be

Quote:

((666+666)/666)^(13-(13+13)/13)-13-13-(666+666)/666

2020-11-25, 16:00	#1
petrw1 1976 Toyota Corona years forever! "Wayne" Nov 2006 Saskatchewan, Canada 2³×569 Posts	13x666=2020 In honor of UncWilly's New Math: https://www.mersenneforum.org/showpo...postcount=1068 Find a formula using only 13 and 666 to get 2020. You can only use +. -, x, /, ^, !, √ 1. Find an answer with the fewest numbers (not digits). 2. Find an answer with the same number of each; and the fewest. For example my first attempt uses 11 numbers. So its an answer for 1. but not for 2. 666+666+666+13+13-(13+13)/13-(666+666)/666.

2020-11-25, 18:51	#8
matzetoni Feb 2019 2×41 Posts	Trial and error got me down to 9 numbers: 2020 = 666+((13+13)/13)(666+13-(13+13)/13) Last fiddled with by matzetoni on 2020-11-25 at 18:59*

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2020-11-25, 16:30	#2
Viliam Furik "Viliam Furík" Jul 2018 Martin, Slovakia 13×29 Posts	131313-13*13-(13+13+13+13+13+13+13+13)/13 = 2020

2020-11-25, 17:11	#5
VBCurtis "Curtis" Feb 2005 Riverside, CA 3³·173 Posts	In the spirit of the original formula, solutions should use both 13 and 666.

2020-11-25, 17:19	#6
Gelly May 2020 29₁₀ Posts	Trivial improvement to the original solution - 10 numbers 666+666+666-(666+666+666+666)/666+13+13

2020-11-25, 17:39	#7
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 2×2,909 Posts	Not much of a record but the first to use ^ (13+13+13+13)/13 + (13+13/13)(13-13/13)^((13+13)/13) 7 of each (666+666+666+666)/666 + (13+666/666)(13-13/13)^((13+13)/13)

2020-11-25, 19:48	#10
Ensigm Aug 2020 1110010₂ Posts	((666+666)/666)**(13-(13+13)/13)-13-13-(666+666)/666 6 each.