20200116, 09:14  #1 
Mar 2018
1000001111_{2} Posts 
number of digits
pg(215), pg(69660), pg(92020) and pg(541456) are prp with 215, 69660, 92020, 541456 multiple of 43
pg(215) has 130 digits pg(69660) has 41940 digits pg(92020) has 55402 digits pg(541456) has 325990 digits so when pg(k) is prp and k multiple of 43 pg(k) has a number of digits multiple of 3 only if k is a multiple of 3. 
20200116, 18:23  #2 
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2^{2}×2,333 Posts 

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