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Old 2020-01-16, 09:14   #1
enzocreti
 
Mar 2018

10000011112 Posts
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pg(215), pg(69660), pg(92020) and pg(541456) are prp with 215, 69660, 92020, 541456 multiple of 43


pg(215) has 130 digits
pg(69660) has 41940 digits
pg(92020) has 55402 digits
pg(541456) has 325990 digits


so when pg(k) is prp and k multiple of 43


pg(k) has a number of digits multiple of 3 only if k is a multiple of 3.
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Old 2020-01-16, 18:23   #2
Batalov
 
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Mar 2008
Phi(4,2^7658614+1)/2

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Quote:
Originally Posted by enzocreti View Post
pg(k) has a number of digits multiple of 3 only if k is a multiple of 3.
Nonsense.

How many digits pg(4) has?
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