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#12 |
Aug 2002
Buenos Aires, Argentina
17×79 Posts |
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#13 |
(loop (#_fork))
Feb 2006
Cambridge, England
2×3,191 Posts |
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115^128+1 completed (250 curves at 1e7 were enough); result in factordb.com
101^128+1 also completed So: 400 curves at 1e7 on the not-previously-fully-factored numbers in {94..115}^128+1. This took one night on 16 threads on a macpro. 35^128+1 currently finishing linalg Last fiddled with by fivemack on 2010-09-04 at 07:50 |
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#14 |
(loop (#_fork))
Feb 2006
Cambridge, England
2×3,191 Posts |
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35^128+1 = 2 * 769 * 77310721 * 465774259823008864434412748488285224928909076514051885029488061896961 * P118
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#15 |
Banned
"Luigi"
Aug 2002
Team Italia
12C316 Posts |
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#16 |
A Sunny Moo
Aug 2007
USA (GMT-5)
11000011010012 Posts |
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#17 |
Oct 2004
Austria
2×17×73 Posts |
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#18 |
(loop (#_fork))
Feb 2006
Cambridge, England
2·3,191 Posts |
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yes; x^5+35^2, x=35^26; alim=rlim=15M, Q=7.5M-17.5M, 28-bit large primes. 494 CPU-hours sieving on 8x K10+3x core2, 48 CPU-hours on 4xphenom to do the matrix step. A trivial exercise.
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#19 |
Banned
"Luigi"
Aug 2002
Team Italia
3×1,601 Posts |
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#20 |
Mar 2003
New Zealand
115710 Posts |
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I found this p44 factor after about 500 curves with B1=11e6: 14571454116637488440882751359138387691414529 | 8^(2^8) + 5^(2^8)
If anyone wanted to finish some of these off with GNFS, I think the two smallest remaining composites (with bases <= 12) are now: 11^(2^8) + 3^(2^8) = 2 . 3430486387626057217 . 1826300595737909153428993580626433 . 132980092956629419115138154564331009 . 11765487608073254883107740674172674049 . C143 8^(2^8) + 5^(2^8) = 206102775026177 . 25083346678208656976952833 . 14571454116637488440882751359138387691414529 . C149 |
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#21 | |
"Robert Gerbicz"
Oct 2005
Hungary
5×172 Posts |
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#22 | |
Mar 2003
New Zealand
115710 Posts |
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