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Old 2020-08-02, 11:47   #1
Xyzzy
 
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Default August 2020

http://www.research.ibm.com/haifa/po...ugust2020.html
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Old 2020-08-02, 17:11   #2
Dieter
 
Oct 2017

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For my understanding:

„(0,1,2) is a losing position since the possible moves result in the positions (0,1,1) or (0,0,2)“

(0,1,2) can result in the position (0,0,1), too?
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Old 2020-08-03, 16:14   #3
tgan
 
Jul 2015

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Quote:
Originally Posted by Dieter View Post
For my understanding:

„(0,1,2) is a losing position since the possible moves result in the positions (0,1,1) or (0,0,2)“

(0,1,2) can result in the position (0,0,1), too?
You are correct however (0,0,1) is also loosing
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Old 2020-08-29, 08:33   #4
LaurV
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Quote:
Originally Posted by Dieter View Post
(0,1,2) can result in the position (0,0,1), too?
Yes, in two ways, either taking one from last two stacks, or taking 2 from the last stake, which goes to (0,1,0), but for the purpose of the game, (0,0,1) and (0,1,0) are the same. Stacks are commutative.
However, as tgan said, that is also losing, so the (0,1,2) is losing, you can't force a win.
P.S. I see they fixed it, adding the (0,0,1) to the list.

Last fiddled with by LaurV on 2020-08-29 at 08:34
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