20051225, 04:03  #221 
Jun 2003
627_{16} Posts 
No factors for 2^p+1/3 under 4.2 billion. (newpgen crashes after this)
I am currently using newpgen, is there a way to get prime95 to trial factor 2^p+1 numbers? Citrix Last fiddled with by Citrix on 20051225 at 04:08 
20051225, 04:08  #222  
Jun 2003
627_{16} Posts 
Quote:
For right now I reserve 16777213. Citrix 

20051225, 04:23  #223  
P90 years forever!
Aug 2002
Yeehaw, FL
2·3·1,193 Posts 
Quote:
On another note, someone could start a distributed computing project looking for primitive trinomials. Richard Brent would probably be thrilled. 

20051225, 04:37  #224 
"Mike"
Aug 2002
1E78_{16} Posts 
A bit off topic:
Please test this page and let me know if it displays properly: http://www.mersenneforum.org/txt/p30.txt I think I have it set up to determine if the requesting browser supports gzip and then it sends the gzipped version to the browser, which then (hopefully) uncompresses it on the fly. So far the page works in FF1.5 and IE6. If it works then we'll cut our bandwidth by half. Thanks! 
20051225, 04:46  #225  
Aug 2002
DF_{16} Posts 
Quote:


20051225, 04:47  #226  
Jun 2003
3^{2}·5^{2}·7 Posts 
Quote:
Any programs to do so? Also PFGW might be a problem for me. I like Prime95. Also what are primitive trinomials? Citrix 

20051225, 04:56  #227 
Jun 2003
627_{16} Posts 
If primitive trinomials are x^2+x+1 then they have been tested for base 2 and are being tested by the PIES project for other bases.There is alot of scope of speed up for the project.
Citrix Last fiddled with by Citrix on 20051225 at 04:57 
20051225, 05:06  #228 
P90 years forever!
Aug 2002
Yeehaw, FL
7158_{10} Posts 
Google "primitive trinomials". They are related to Mersenne primes. Brent has finished up to M39, but the next few will require quite a bit of horsepower  but at least it would have an achievable, finite goal.

20051225, 05:24  #229 
Jun 2003
3^{2}·5^{2}·7 Posts 
NO factor upto 10^17 for 2^P+1/3. Are there any programs to test higher?
Citrix 
20051225, 10:49  #230  
Dec 2003
216_{10} Posts 
Quote:


20051225, 11:02  #231 
"Nancy"
Aug 2002
Alexandria
2^{5}·7·11 Posts 
ECM has a distinct disadvantage here in that it does not get the factor 30402457 in q1 when q2^30402457+1. Better to do some P1 first, which I'm doing right now.
Alex Edit: I trial divided to 10^18, no factor Edit: P1 with B1=100k, B2=4M, no factor Last fiddled with by akruppa on 20051226 at 00:25 
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