20170516, 16:52  #1 
"Matthew Anderson"
Dec 2010
Oregon, USA
2·3·7·17 Posts 
This is a sequence with integers
Hi Mersenneforum,
Maple software is so overwhelming. It can algebraically solve almost anything. I don't type Pari much. But I try to shine a light on some math / computer topics. Request for comments. Regards, Matt 
20170517, 00:00  #2  
"Forget I exist"
Jul 2009
Dumbassville
8384_{10} Posts 
Quote:
x1=1 x2=3 x[a]=6*x[a1]+5*x[a2] x[3]=18+5 =23 x[4]=138+15 =153 etc. edit:okay maybe not but you do eliminate a constant factor of two and get another recurrence that is always odd. Last fiddled with by science_man_88 on 20170517 at 00:02 

20170517, 13:11  #3 
"Forget I exist"
Jul 2009
Dumbassville
20C0_{16} Posts 
more generally there are 4 ways for the first values to be setup within the integers mod 2
1 0 1 1 0 0 0 1 and 4 ways for the coefficients ( same as above) these combinations result in: Code:
(10:02) gp > my(a=[0,0]);for(x=1,10,a=concat(a,1*a[#a]+0*a[#a1]));a %1 = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] (10:03) gp > my(a=[0,1]);for(x=1,10,a=concat(a,1*a[#a]+0*a[#a1]));a %2 = [0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1] (10:03) gp > my(a=[1,1]);for(x=1,10,a=concat(a,1*a[#a]+0*a[#a1]));a %3 = [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1] (10:03) gp > my(a=[1,0]);for(x=1,10,a=concat(a,1*a[#a]+0*a[#a1]));a %4 = [1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] (10:03) gp > my(a=[1,0]);for(x=1,10,a=concat(a,0*a[#a]+0*a[#a1]));a %5 = [1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] (10:04) gp > my(a=[1,1]);for(x=1,10,a=concat(a,0*a[#a]+0*a[#a1]));a %6 = [1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] (10:04) gp > my(a=[0,1]);for(x=1,10,a=concat(a,0*a[#a]+0*a[#a1]));a %7 = [0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] (10:04) gp > my(a=[0,0]);for(x=1,10,a=concat(a,0*a[#a]+0*a[#a1]));a %8 = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] (10:04) gp > my(a=[0,0]);for(x=1,10,a=concat(a,0*a[#a]+1*a[#a1]));a %9 = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] (10:05) gp > my(a=[1,0]);for(x=1,10,a=concat(a,0*a[#a]+1*a[#a1]));a %10 = [1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0] (10:05) gp > my(a=[0,1]);for(x=1,10,a=concat(a,0*a[#a]+1*a[#a1]));a %11 = [0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1] (10:05) gp > my(a=[1,1]);for(x=1,10,a=concat(a,0*a[#a]+1*a[#a1]));a %12 = [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1] (10:05) gp > my(a=[1,1]);for(x=1,10,a=concat(a,1*a[#a]+1*a[#a1]));a %13 = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144] (10:06) gp > my(a=[0,1]);for(x=1,10,a=concat(a,1*a[#a]+1*a[#a1]));a %14 = [0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89] (10:06) gp > my(a=[0,0]);for(x=1,10,a=concat(a,1*a[#a]+1*a[#a1]));a %15 = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] (10:06) gp > my(a=[1,0]);for(x=1,10,a=concat(a,1*a[#a]+1*a[#a1]));a %16 = [1, 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55] 
20170517, 13:31  #4 
"Harry Willam"
May 2017
USA
2^{2}×5 Posts 
Draw one line on this equation to make it correct
5+5+5+5= 555 Last fiddled with by Harrywill on 20170517 at 13:35 
20170517, 14:09  #5 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 

20170517, 15:49  #6 
Romulan Interpreter
Jun 2011
Thailand
10010010011001_{2} Posts 

20170518, 08:33  #7 
Mar 2006
Germany
43·67 Posts 
[offtopc]Connect the upper and left line end points of one plus sign.[/offtopc]
Last fiddled with by kar_bon on 20170518 at 08:34 
20170523, 21:38  #8 
"Matthew Anderson"
Dec 2010
Oregon, USA
2·3·7·17 Posts 
Hi Mersenneforum,
So here is another Fibonacci like sequence with different starting values. Regards, Matt 
20170523, 21:59  #9 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 

20170527, 01:39  #10 
"Matthew Anderson"
Dec 2010
Oregon, USA
2·3·7·17 Posts 
Hi Mersenneforum and others,
New sequence, new integers This one is c(r) = 8*c(r1)+9*c(r2). I am not saying that there is any special significance in this one, but check it out. Regards, Matt 
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