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#1 |
Apr 2012
Brady
5·7·11 Posts |
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..short for math and art.
Here is how excited you should be about this post.. https://www.youtube.com/watch?v=4a2ZQtvMhRg This is the reason behind the post: http://www.concinnitasproject.org/portfolio/ Perhaps these could be used as a "Rorschach" test. Last fiddled with by jwaltos on 2021-01-15 at 05:41 |
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#2 |
Dec 2012
The Netherlands
11×151 Posts |
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For anyone who hasn't seen it yet:
Proofs from The Book |
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#3 | |
Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
23×463 Posts |
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The basic idea is that F_n - 2 = 2^2^n - 1 = (2^2^(n-1) +1) (2^2^(n-1) -1) = F_{n-1} * (F_{n-1} -2) by the difference of squares factorization formula and noting that F_n is co-prime to F_m when m != m. |
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#4 | |
Dec 2012
The Netherlands
31758 Posts |
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And the 3rd one uses Mersenne numbers (for prime p, a prime factor of \(M_p\) is greater than p). |
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#5 | |
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
3×5×307 Posts |
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#6 |
Apr 2012
Brady
5·7·11 Posts |
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#7 | |
Apr 2012
Brady
5·7·11 Posts |
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There is more to this than meets the eye. Last fiddled with by jwaltos on 2021-01-16 at 06:06 |
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