20170221, 10:29  #12  
Mar 2015
Australia
122_{8} Posts 
Quote:
I've only explored sigma(z)z, so I don't know if iterating sigma(z) is interesting or not. 

20170223, 11:12  #13 
Oct 2011
3·5·17 Posts 
Thank you for your help Andrew.

20170508, 07:49  #14 
Mar 2015
Australia
2×41 Posts 
I've been doing a bit more searching this year, here is my latest list which has 304 gaussian amicable pairs. It's getting harder to find them now!

20170828, 09:11  #15 
Mar 2015
Australia
2·41 Posts 
A big update, now have 423 pairs! Many of these come from searching a common factor
with 4 extra small factors which I had done very little with earlier. Plus also many from 3 extra small factors Andrew 
20171214, 10:05  #16 
Mar 2015
Australia
2·41 Posts 
More of the same searching, now 515 pairs
Andrew 
20180111, 11:57  #17 
Mar 2015
Australia
2×41 Posts 
I discovered that pari when writing a factorisation to a file leaves it on one line! So with
a bit of extra find/replace manipulation in Word here is a list of the pairs with factorisations. There still could be a number of errors in this so if you spot any thing odd or just plain wrong please let me know! 
20180617, 07:58  #18 
Mar 2015
Australia
1010010_{2} Posts 
Next update at 600 pairs, very close!

20180624, 08:27  #19 
Mar 2015
Australia
2·41 Posts 
Pair 600 found today
Again please let me know if you spot any errors. Andrew 
20181130, 08:18  #20 
Mar 2015
Australia
2×41 Posts 
Looks like I've probably reached 750 pairs, will do a stocktake and add some comments over the weekend!
Andrew 
20181204, 06:33  #21 
Mar 2015
Australia
2·41 Posts 
760 pairs!
I've found quite a few in the last few weeks, including some new largest pairs, as I had the idea to search on (1+I)^m * (1+2I)^n * (1+4I) (multiplied by extra prime factors) which I'd never done before, had only used two of these factors at a time. I've found pairs using this with m up to 15 and n up to 4. I haven't found any pairs of any form with (1+4I) being a power of 2 or more. Andrew 
20190809, 10:07  #22 
Oct 2011
3·5·17 Posts 
Has anyone ever tried to find complex social chains of any length other than 2 (other than complex amicable numbers presented by Andrew Walker just above) ?

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