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Old 2014-11-26, 04:48   #23
MichelMarcus
 
Nov 2011
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Yes, powers of 3, you're right, sorry for the mistake.
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Old 2014-11-26, 04:56   #24
EdH
 
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"Ed Hall"
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Quote:
Originally Posted by MichelMarcus View Post
Yes, powers of 3, you're right, sorry for the mistake.
I thought maybe you were checking to see if I actually did look it over.
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Old 2014-11-26, 16:40   #25
MichelMarcus
 
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LOL
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Old 2014-11-29, 10:30   #26
MichelMarcus
 
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Jamais 2 sans 3 ?
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Old 2014-11-30, 03:37   #27
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Quote:
Originally Posted by MichelMarcus View Post
Jamais 2 sans 3 ?
Je ne comprends pas. Les sequences ou facteurs?
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Old 2014-11-30, 14:14   #28
MichelMarcus
 
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Ah, in french we say "jamais deux sans trois", to mean that something that occured twice, can happen another time.
I was trying to anticipate your 3rd announcement of a 4-sociable group.
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Old 2014-11-30, 15:57   #29
EdH
 
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Quote:
Originally Posted by MichelMarcus View Post
Ah, in french we say "jamais deux sans trois", to mean that something that occured twice, can happen another time.
I was trying to anticipate your 3rd announcement of a 4-sociable group.
My French is very limited, although I was able to understand a user manual that had all languages except English a while back. Your correct intent did cross through as possible, but I couldn't be sure.

The second one was quite a surprise. I had not expected another so soon. I would really be surprised to find a third in the near future - delighted, but surprised.

Merci, pour vos pensees aimables.
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Old 2014-12-05, 11:12   #30
MichelMarcus
 
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You're welcome.
I have updated the "Construction rule" file in A214134.
Best regards.
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Old 2014-12-05, 15:34   #31
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Quote:
Originally Posted by MichelMarcus View Post
You're welcome.
I have updated the "Construction rule" file in A214134.
Best regards.
Thanks. I'll look it over.
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Old 2014-12-08, 12:49   #32
Drdmitry
 
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Nov 2011

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I revised my old program for searching aliquot cycles and rewrote it. So now it can search for all cycles inside any given interval. On my laptop (one core of Intel i5-3230M) it takes about 34 -- 34.3 secs to go through 10^7 numbers of size around 10^14. EdH, May I ask you how it compares with your program's speed?
If someone is interested in doing a full search of aliquot cycles up to 10^14 (or maybe even up to 10^15?) I can try to make a usable version of my program and publish it here.

Last fiddled with by Drdmitry on 2014-12-08 at 12:50
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Old 2014-12-08, 15:04   #33
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Sorry, I made a stupid mistake when counted the range of numbers. It is actually much slower: about 26 -- 26.3 secs per 10^6 numbers of size around 10^14.
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