20120403, 18:53  #12 
Apr 2010
Over the rainbow
2352_{10} Posts 
Raman, if you really want, i can advance it a few iteration.. But from what i know of you (various post here) , you seem to be able to do it by yourself.

20120403, 19:54  #13 
Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 89<O<88
3·29·83 Posts 
What's most interesting is that the last two lines are remarkably close to each other. They share their 9 most significant decimal digits, out of 111. Amazing.

20120403, 20:44  #14 
Nov 2008
2·3^{3}·43 Posts 
If a line factors as 2*3*p = 6p, then the next line will be 1+2+3+6+p+2p+3p = 6p+12 which is only 12 bigger. Very small increases are common for the perfect number drivers.

20120403, 21:31  #15 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
yeah I just looked up 2*3*5 and it stays with 6*(p+2) sums until it hits 144 = 12^2 at iteration 6. this seems to lead me to the conclusion that xp would lead to (sigma(x)x)*p+sigma(x) but I might have missed something else important like they must be of the form sigma(x)=y*x or something ( tested and my computer says sigma(x)=y*x , fits every number so far tested, and I tested the broader claim for 90 claiming x=(2*3^2);p=5 and it worked to predict the next line).
Last fiddled with by science_man_88 on 20120403 at 22:00 
20120403, 23:53  #16  
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 
Quote:
and sigma(x)=y*x leads to: ((y*x)x)*p+(y*x) = z*x*p+y*x = (z*p+y)*x so if you know the driver/guide controlling it you can factor the lower number z*p+y 

20120404, 04:17  #17  
Noodles
"Mr. Tuch"
Dec 2007
Chennai, India
3×419 Posts 
Quote:
But, you need to reply to the following question What is being the smallest Aliquot sequence to merge with the 3*2[sup]164[/sup].i2434 = 1231600? Whether if it is being 10^{7}10, 10^{11}, 10^{13} what is being the good software available to find out what the smallest Aliquot Sequence merging with some of the above mentioned sequence? at all, The last, but not the least, what is being special from the number 4198862272 

20120404, 09:02  #18  
"Frank <^>"
Dec 2004
CDP Janesville
2122_{10} Posts 
Quote:
Quote:
I found the above merge through the simple expedient of searching all my local .elf files for a prime from your sequence.....a little slow, but elegantly simple. Greebley has uploaded some files that contain basically everything, look at the latest threads to find info about that.... [Edited to add: There is also a UBASIC program that can check 2 specific sequences to see if they merge, but it doesn't seem to be on Wolfgang's page right now and Clifford's site is down (gone?)] Quote:
Last fiddled with by schickel on 20120404 at 09:07 

20120404, 12:02  #19  
Noodles
"Mr. Tuch"
Dec 2007
Chennai, India
3·419 Posts 
Quote:
the smallest? It is certainly being the smallest if it is being present within the set from the kar_bon's rieselprime.de list; seeing that the smaller number 508980 is available, but that the larger number 772032 is not at all, at once. Quote:
some more candidates (numbers) to test the merging with, whether. 9999990, 333333 (5400), 3840, 7680, 315^{2}, 945^{2} 888, 828, 990, 2160 Okay, alright then but that the Can anyone be able to observe thereby guessing the significance from this following sequence? 100, 98.415, 97.2, 95.65938, 94.143178827, 92.98091736, 90.3981141, 90 96 × 1.024 = 98.304  98.415 = 0.111 > 1/9; 1.024 = 896/875 5^{3} × 1.024 = 2^{7} => 2^{10} ≈ 10^{3} 2^{93} ≈ 10^{28} => 2^{65} ≈ 5^{28} 2^{196} ≈ 10^{59} => 2^{137} ≈ 5^{59} 2^{485} ≈ 10^{146} => 2^{339} ≈ 5^{146} 2^{2136} ≈ 10^{643} => 2^{1493} ≈ 5^{643} 2^{13301} ≈ 10^{4004} => 2^{9297} ≈ 5^{4004} Last fiddled with by Raman on 20120404 at 13:02 

20120404, 12:16  #20 
"Frank <^>"
Dec 2004
CDP Janesville
2×1,061 Posts 

20120404, 16:33  #21 
Apr 2010
Over the rainbow
2^{4}×3×7^{2} Posts 
I interpret it as ' I'm not entirly confident on that'

20120404, 19:18  #22  
Mar 2006
Germany
2^{8}·11 Posts 
Quote:
3*2^164:i2421 = 508980:i3 = 3775104 So 1231600 = 508980:i16 My lists of Aliquot sequences on that page are out of date! Last fiddled with by kar_bon on 20120404 at 19:26 

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