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Old 2014-07-15, 16:26   #6
R.D. Silverman
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Nov 2003

22·5·373 Posts

Originally Posted by science_man_88 View Post
just asking things:

I'm guessing it's known that (2^{p-1}\eq 1 \text { mod p^2}) == (2^{2n-1}-1\eq 2n^2+2n \text { mod 4n^2+4n+1}) where 2n+1 =p; if so has anything useful come out of it ?
Would a moderator please move this (and succeeding) gibberish to the crank
math sub-forum?
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