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Old 2006-09-27, 23:09   #10
Wacky's Avatar
Jun 2003
The Texas Hill Country

20728 Posts

Originally Posted by ewmayer View Post
Assume the initial circle is centered at (0,0) and has radius 1. Now draw a pair of circles of half that radius, one centered at (0, 1/2), the other at (-1/2, 0). These intersect (in the sense of touching at a single point) at (0,0), and thus subdivide the large circle into 4 equal-area subsets, two of which are circles, two of which are not.
I would claim that this is a "radial" solution since it has point symmetry about the origin.

Last fiddled with by Wacky on 2006-09-27 at 23:21
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