Quote:
Originally Posted by hhh
So, for the sake of understanding:
is it like I described, space $R^2$, for any $x\inR^2$ you take a U[0,1] r.v., all iid? This floor would be as I said highly discontinuous.
Or do you mean by "uniformly random" "arbitrary, but continuous". In this case, I can vaguely figure how it should work with what you cited (I think you meant Brouwer's fixed point theorem).

Highly discontinuous? Indeed!! It is nowhere continuous.