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Old 2020-03-26, 19:44   #4
Dr Sardonicus
 
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Feb 2017
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Quote:
Originally Posted by retina View Post
Very good.

If we assign:

A = 1 + 1 + 1 + 1 + 1 + 1 + ...
B = 1 + 2 + 3 + 4 + 5 + 6 + ...

Then B - A = B, since pairwise subtraction gives 0 + 1 + 2 + 3 + ... = 1 + 2 + 3 + ...

Therefore A = 1 + 1 + 1 + 1 + 1 + 1 + ... = 0
OTOH, we have

1 + A = A

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