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Aliquot sequences that start on the integer powers n^i
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2021-08-09, 12:44
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bur
Aug 2020
79*6581e-4;3*2539e-3
17·29 Posts
I finished (2*18^2)^n = (648^2)^n up to n = 50.
For 50 < n < 60 the inial term as has 144-169 digits and since every odd n has factor 3 they decrease very slowly. So I think I'll stop on that base now that it's at a nice n=50.
bur
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