Thread: Can some explain this? View Single Post
2019-09-29, 12:34   #12
wildrabbitt

Jul 2014

6778 Posts

Quote:
 For roots of positive real numbers a, and real values of k, everything is fine -- you've got a real-valued logarithm, defined by an integral.
Can you explain how in

$$64^3 = e^{3log(64)}$$

the real-valued logarithm is defined by an integral and what the integral is?

or rather

$$64^{1/2} = e^{(1/2)log(64)}$$ ? ( as you said roots).

Last fiddled with by wildrabbitt on 2019-09-29 at 12:39