Jun 2003
The Texas Hill Country
2101_{8} Posts

Quote:
Originally Posted by ZetaFlux
Problem 6: Note that this solution doesn't require the table to be round. Only that it have a line of symmetry.

Isn't it actually a Point of Symmetry? An equilteral triangle has a line of symmetry which is he perpendicular bisector of the base. And placement that includes a portion of the line cannot be countered by a symetrically opposite move. Therefore, the last player who is able to place his coin such that it crosses the line would be the winner. But that is not necessarily the first player.
