View Single Post 2020-09-10, 13:20 #1 Viliam Furik   "Viliam Furík" Jul 2018 Martin, Slovakia 52×13 Posts Python script for search for factors of M1277 using random k-intervals Code: import numpy as np from random import randint f = open("m1277.txt", "a") def tf1277(k, r): expos = np.zeros((4, r), int) p = 1277 y = 0 z = 0 e1 = 2555 e2 = 3832 e3 = 7663 e4 = 8940 pbinary = [] q = p while q > 0: if q % 2 == 0: pbinary.append(0) q //= 2 if q % 2 == 1: pbinary.append(1) q //= 2 pbinary.reverse() for x in range(4): for prime in [3, 5, 7, 11, 13, 17, 19, 23, 29]: for a in range(prime + 5): if x == 0: e = e1 elif x == 1: e = e2 elif x == 2: e = e3 else: e = e4 if ((a + k) * 10216 + e) % prime == 0: c = a while c < r: expos[x][c] = 1 c += prime break for a in range(len(expos)): if expos[a] == 0: c = 1 kp = (k + a) * 10216 + 2555 for d in pbinary: c **= 2 if d == 1: c *= 2 c %= kp if c == 1: print("-------------------------") print("factor = ", kp) print("k = ", (kp - 1) // 2 // 1277) f.write("\n") f.write("factor = " + str(kp)) f.write("\n") f.write("k = " + str((kp - 1) // 2 // 1277)) f.write("\n") quit() if y == 1000: y = 0 z += 1 print(z * 1000) y += 1 for a in range(len(expos)): if expos[a] == 0: c = 1 kp = (k + a) * 10216 + 3832 for d in pbinary: c **= 2 if d == 1: c *= 2 c %= kp if c == 1: print("-------------------------") print("factor = ", kp) print("k = ", (kp - 1) // 2 // 1277) f.write("\n") f.write("factor = " + str(kp)) f.write("\n") f.write("k = " + str((kp - 1) // 2 // 1277)) f.write("\n") quit() if y == 1000: y = 0 z += 1 print(z * 1000) y += 1 for a in range(len(expos)): if expos[a] == 0: c = 1 kp = (k + a) * 10216 + 7663 for d in pbinary: c **= 2 if d == 1: c *= 2 c %= kp if c == 1: print("-------------------------") print("factor = ", kp) print("k = ", (kp - 1) // 2 // 1277) f.write("\n") f.write("factor = " + str(kp)) f.write("\n") f.write("k = " + str((kp - 1) // 2 // 1277)) f.write("\n") quit() if y == 1000: y = 0 z += 1 print(z * 1000) y += 1 for a in range(len(expos)): if expos[a] == 0: c = 1 kp = (k + a) * 10216 + 8940 for d in pbinary: c **= 2 if d == 1: c *= 2 c %= kp if c == 1: print("-------------------------") print("factor = ", kp) print("k = ", (kp - 1) // 2 // 1277) f.write("\n") f.write("factor = " + str(kp)) f.write("\n") f.write("k = " + str((kp - 1) // 2 // 1277)) f.write("\n") quit() if y == 1000: y = 0 z += 1 print(z * 1000) y += 1 while True: tf1277(randint(58000000000000000, 2 ** (1277 / 2) / 1277 / 2), 1000000) Hello, I have made the above Python script, that is called with random starting k value, and then tests about 1263000 sived-out k's above that value. It uses a grid of zeroes to sieve k's and combines the facts that factors must be 2*k*p+1 and also 1 or 7 (mod 8) - so it only tests factors that are 2555, 3832, 7663, 8940 (mod 10216). If there is a mistake (either logical or mathematical) in my script, I'll be grateful for pointing out. I would also be grateful if somebody could help me with making the code runnable on a Nvidia GPU with CUDA (or in OpenCL, if it's easier), without necessarily using FFT or Barrett multiplication. (But if somebody is willing to explain, I'll be happy to listen, or read...). And for the last, if you want, you can try to find the factor yourself with that code. It takes my CPU about 12 seconds on average to go through random range of size 10216000000 (that is difference between largest and smallest k tested). So if I was to randomly check the equivalent number of ranges (untested range from 2^67 to 2^639 divided by range size 10216000000), it would take me... about 2*10^172 years . But if more people engage in search, probability increases (unfortunately it's only slight change). So if you want to help, you can run the script any time you like. If you want to help more, you can help with improving the speed of the script.  