factoring 2ⁿ2 equivalent to factoring 2ⁿ1(I think)
2^{n}1= a*b
factoring 2^{n}2 equivalent to factoring 2^{n}1
if this condition is met (a1) divided by (b1)
then 2^{n}1 =1 mod b1
example
M11 = 0 mod 23 and 88 =0 mod 22
2^{11}2 = 0 mod 22
M23 = 0 mod 47
2^{23}2 = 0 mod 46
M73 = 0 mod 439
2^{73}2 = 0 mod 438
M83 = 0 mod 167
2^{83}2 = 0 mod 166
M131 = 0 mod 263
2^{131}2 = 0 mod 262
Last fiddled with by baih on 20200913 at 18:42
