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Old 2020-09-13, 09:34   #8
JeppeSN
 
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"Jeppe"
Jan 2016
Denmark

2428 Posts
Question

Quote:
Originally Posted by LaurV View Post
and based on the fact that the series s(n)=2n^2-1 for integer n, is a divisibility series.
How? For example, 7 divides 70, but s(7) = 2*7^2 - 1 = 97 does not divide s(70) = 2*70^2 - 1 = 9799. Clearly enough, 97 divides 9797, hence 97 leaves a remainder of 2 when dividing into 9799?

It is true that M(p) = 2^p - 1, for odd p, can be written as s(n); you take n = 2^{(p-1)/2}.

For example, M(101) = 2^101 - 1 = 2*(2^50)^2 - 1 = s(2^50).

Not sure if the relation n = 2^{(p-1)/2} is related to masser's question.

/JeppeSN
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