Thread: Rocky table View Single Post
 2007-03-21, 15:32 #10 hhh     Jun 2005 17516 Posts So, for the sake of understanding: is it like I described, space $R^2$, for any $x\inR^2$ you take a U[0,1] r.v., all iid? This floor would be as I said highly discontinuous. Or do you mean by "uniformly random" "arbitrary, but continuous". In this case, I can vaguely figure how it should work with what you cited (I think you meant Brouwer's fixed point theorem).