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Old 2004-04-24, 06:00   #2
jinydu's Avatar
Dec 2003
Hopefully Near M48

2·3·293 Posts

I don't really know how to take the log of complex numbers, but I'll start off like this:

phi = 2 cos (log ((i^2))/5*i)

phi = 2 cos (log (-1)/5i)

phi = 2 cos (log (i/5))

phi = 2 cos (log i - log 5)

I would suggest applying the compound angle formula for cosine at this point.
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