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Old 2014-07-14, 23:06   #1
science_man_88
 
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"Forget I exist"
Jul 2009
Dumbassville

838410 Posts
Default Some arithmetic...

just asking things:

I'm guessing it's known that (2^{p-1}\eq 1 \text { mod p^2}) == (2^{2n-1}-1\eq 2n^2+2n \text { mod 4n^2+4n+1}) where 2n+1 =p; if so has anything useful come out of it ?

Last fiddled with by science_man_88 on 2014-07-14 at 23:13 Reason: took a +1 away after realizing the error.
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