want an example of what I mean ? too bad I'll give you one anyways lol.
for p=11 p=3 mod 8
for factors 7 mod 8
k=1,5,9,etc. (4n+1)
for 1 mod 8
k=0,4,8,12
since they can be 6n+1 or 6n1
since 11= 5 mod 6
6n+1 k=0,3,6,9, (3x+0)
6n1 k = 1,4,7 (3x+1)
if we say we need at least 1 factor of the same type mod 6 then we only have to check when 4n+1 or 4n match up with 3x+1 and we should find possible factors k= 1,13,etc. because 4n+1 meets 3x+1 every fourth value and every 3rd value greater than index =2 for 4n this limits it to at most if we can figure on thing out i could narrow it down to finding factors on one or the other k list for mod 8 but anyways.
