Thread
:
A small question from the lost book
View Single Post
2021-11-18, 13:17
#
5
Dr Sardonicus
Feb 2017
Nowhere
5·7·13
2
Posts
Quote:
Originally Posted by
RomanM
i.e. A^2==B^2 mod p, p=x^2(x^3+y^3); May be this too obviosly and known???
<snip>
Factor (2x
3
+ y
3
)
2
- y
6
as the difference of two squares.
Dr Sardonicus
View Public Profile
Find More Posts by Dr Sardonicus
^{2}\equiv y^{6}\; mod\;x^{2}(x^{3}+y^{3}); \; y\neq0,\; x,y\in Z)