Thread: Advice for large SNFS jobs? View Single Post
 2013-01-21, 19:41 #1 ryanp     Jun 2012 Boulder, CO 2·7·13 Posts Advice for large SNFS jobs? Hi all, I'm working on factoring (2801^83-1)/2800 using a modified factmsieve.py -- and yes, I have a cluster available to me... :) factmsieve tells me at the get-go: Fri Jan 18 09:58:41 2013 -> Estimated minimum relations needed: 5.53168e+08 I'm able to make it up to about 200M relations with the default parameters (starting at rational q from 238450000, FAMAX = 476900000) before hitting GGNFS' limit: it can't handle special q >= 2^30 - 1. Does anyone have any advice for what to do with jobs this big? Try to change the sieving window somehow? (And if so -- to what)? Here's the polynomial I'm using: Code: n: 4784427753962229503583191777575386925462640502543527013793934480234680863804447852383959785408791045459809147067083157248015897910382151758867576620242257524246139326208569043470479714282260046673050230392057658284742406595942226610043596316622243579005395853667131475327572196568483 m: 1829715316371090533839726975772594414416841479201 deg: 6 skew: 0 type: snfs c6: 1 c0: -2801 which gives the factor base: Code: N 4784427753962229503583191777575386925462640502543527013793934480234680863804447852383959785408791045459809147067083157248015897910382151758867576620242257524246139326208569043470479714282260046673050230392057658284742406595942226610043596316622243579005395853667131475327572196568483 SKEW 3.75 A6 1 A0 -2801 R1 1 R0 -1829715316371090533839726975772594414416841479201 FAMAX 476900000 FRMAX 476900000 SALPMAX 4294967296 SRLPMAX 4294967296