Quote:
Originally Posted by a1call
I disagree.
If Primes are products of distinct primes then:
4 > 2 > 1
25 > 5 > 1
100 > 20 > 4 > 2 > 1
121 > 11 > 1
Bob wins.
Else if Primes arenot products of distinct primes then:
4, 25 and 121 have no winners so Alice will have the only choice of choosing 100 and then:
100 > 10 > 1
Bob wins.

false if the sum is a prime square, the only way not to repeat primes is for Alice to take the sqrt and Bob to divide by the sqrt a second time.